Logic To Find Leap Year In Java

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Logic To Find Leap Year In Java
Logic To Find Leap Year In Java


Logic To Find Leap Year In Java -

Using the Pre Java 8 Calendar API Since Java 1 1 the GregorianCalendar class allows us to check if a year is a leap year public boolean isLeapYear int year As

A If given year divisible by 400 it prints is a leap year if condition false then come to else part b If given year divisible by 100 then inner if condition checks

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Import java util public class LeapYear public static void main String args int year Scanner scan new Scanner System in System out println Enter year year

The logic for checking leap year is as follows A year is a leap year if it is divisible by 4 However if the year is divisible by 100 it is not a leap year unless it is

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How To Find Leap Year In Java In Hindi easily Explained Leap Year

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1 year 400 0 2 year 4 0 3 year 100 0 The first condition year 400 0 will check whether the year 400 reminder is precisely equal to 0 As per the program algorithm any number

To determine the leap year we have two approaches GregorianCalendar isLeapYear int year Custom method to determine leap year No

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A If given year divisible by 400 it prints is a leap year if condition false then come to else part b If given year divisible by 100 then inner if condition checks

Program To Check Leap Year In Java YouTube
Leap Year Program In Java Javatpoint

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Rules to verify A century year a year ending with 00 is a leap year only if it is divisible by 400 For example 1700 is not a leap year as it is not divisible by 400 2000 is a leap

A If given year divisible by 400 it prints is a leap year if condition false then come to else part b If given year divisible by 100 then inner if condition checks

Rules to verify A century year a year ending with 00 is a leap year only if it is divisible by 400 For example 1700 is not a leap year as it is not divisible by 400 2000 is a leap

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