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Second Largest Number In Java
Second Largest Number In Java -
As integer Arrays sorted in descending order 2nd element in the Arrays will be the second largest number We will skip first number which is the largest number using Stream skip method Stream findFirst method will return 2nd largest number in the Arrays Finally we will print 2nd largest number to the console
Public class SecondLargestNumber public static void main String args int var 11 11 11 11 115 11 9 int largest 0 int secLargest 0 if var length 1 largest var 0 secLargest var 0 else if var length 1 largest var 0 secLargest var 1 for int i 1 i
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Java Program To Find The Second Largest And Smallest Element In An
Java Program To Find The Second Largest And Smallest Element In An
You can find the second largest element by following an algorithm that resembles the one that you already have with an additional variable representing the second largest number Currently the next element could be larger than the max or equal to smaller than the max hence a single if is sufficient
1 Declare and initialize an array with numeric values 2 Set the first number as the largest and the second number as the second largest or vice versa based on their values 3 Loop through the array starting from the third element comparing each element with the largest and second largest numbers 4
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40 Find The Largest Number In An Array Javascript Javascript Nerd Answer
40 Find The Largest Number In An Array Javascript Javascript Nerd Answer
Java Program to Find Second Largest Number in An Array Updated on November 15 2023 by Arpit Mandliya Table of Contents hide 1 Overview 2 Introduction to Problem Statement 3 Sort and Return Second Largest Element 4 More Optimized Solution 5 Handling Edge Cases 6 Conclusion
This example shows you how to find the second largest number in an array of java Step 1 Iterate the given array Step 2 first if condition arr i largest If current array value is greater than largest value then Move the largest value to secondLargest and make current value as largest
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https://stackoverflow.com/questions/2615712
Public class SecondLargestNumber public static void main String args int var 11 11 11 11 115 11 9 int largest 0 int secLargest 0 if var length 1 largest var 0 secLargest var 0 else if var length 1 largest var 0 secLargest var 1 for int i 1 i
https://stackoverflow.com/questions/54721094
Very easy answer using java streams public static int secondLargestNumberInArray Integer numbers return Arrays stream numbers sorted Collections reverseOrder skip 1 findFirst get In case you want to use primitive method parameter
Public class SecondLargestNumber public static void main String args int var 11 11 11 11 115 11 9 int largest 0 int secLargest 0 if var length 1 largest var 0 secLargest var 0 else if var length 1 largest var 0 secLargest var 1 for int i 1 i
Very easy answer using java streams public static int secondLargestNumberInArray Integer numbers return Arrays stream numbers sorted Collections reverseOrder skip 1 findFirst get In case you want to use primitive method parameter
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